초록
토양 세척법 중에서 수산화나트륨(NaOH)과 과산화수소(H$_2$O$_2$)를 이용한 토양세척의 주된 반응은 H$_2$O$_2$ 분해시 발생되는 산소기포가 토양에 흡착되어 있는 유류오염물질을 효과적으로 탈착 부상시킨다. 이로 인한 H$_2$O$_2$의 분해속도를 온도에 따른 반응속도 상수를 통해 증명하고, 운전인자를 최적화하기 위하여 NaOH 및 H$_2$O$_2$의 농도와 세척시간, 고액비(soil-water)의 영향을 살펴보았다. 토양세척시 NaOH 수용액상에서 H$_2$O$_2$의 분해속도는 농도에 대해 1차 반응이고, NaOH 0.1 M 이하의 농도에서 반응속도상수 k$_1$은 0.9439 $\times$ exp(-1376.82/RT), 이상의 농도에서 반응속도상수 k$_2$는 17.3588 $\times$ exp(-2320.06/RT)이었다. 아울러, NaOH는 일정농도 이상에서 H$_2$O$_2$ 분해를 촉진시키며, 토양세척 시 최적 NaOH/H$_2$O$_2$ 농도를 반응속도상수를 통해 확인하였다. 또한, 토양세척 시최적조건은 세척시간 15 min, 고액비 1 : 3, NaOH 및 H$_2$O$_2$의 농도는 0.25 M과 0.1 M이 적절하였다.
The main reaction for soil washing with using sodium hydroxide(NaOH) and hydrogen peroxide(H$_2$O$_2$) was desorption and flotation of petrochemical contaminant by means of oxygen bubble. We found the rate of decomposition by rate constant according to various temperature. For the purpose of optimizing the operation factor, we examined the effect of concentration of NaOH and H$_2$O$_2$, washing time, and soil:water ratio. The rate of decomposition for H$_2$O$_2$ in liquid phase is the first order reaction by its concentration. The rate constant of k$_1$ was 0.9439 $\times$ exp(-1376.82/RT) when concentration of NaOH was lower than 0.1 M, and the rate constant of k$_2$ was 17.3588 $\times$ exp(-2320.06/RT) when it was higher than NaOH of 0.1 M. It found that NaOH was facilitated at the beyond of specific concentration. We confirmed the optimum concentration of NaOH/H$_2$O$_2$ by means of rate constants during soil washing. Also, the optimum conditions during soil washing were washing time of 15 min, soil : water ratio of 1 : 3, and NaOH/H$_2$O$_2$ concentration of 0.25 M/0.1 M.
