[ $C_{16}H_{19}O_2N_3CuCl_2\;{\cdot}\;H_2O$ ]

$C_{16}H_{19}O_2N_3CuCl_2\;{\cdot}\;H_2O$의 결정 구조

  • Kim Moon-Jib (Department of Physics, Soonchunhyang University) ;
  • Kim Young-Soo (Department of Physics, Soonchunhyang University) ;
  • Choi Ki-Young (Department of Chemistry Education Kongju National University)
  • 김문집 (순천향대학교 물리학과) ;
  • 김영수 (순천향대학교 물리학과) ;
  • 최기영 (공주대학교 화학교육과)
  • Published : 2004.12.01

Abstract

The structure of $C_{16}H_{19}O_2N_3CuCl_2\;{\cdot}\;H_2O$ has been determined by X-ray diffraction methods. The crystal system is triclinic, space group Pl, unit cell constants. $a=7.6202(9)\; \AA,\; b=8.5943(7) \AA,\; c= 8.6272(6) \AA,\; \alpha= 67.518(6)^{\circ}.\; \beta= 68.043(8)^{\circ},\; \gamma=74.370(8)^{\circ},\; V=478.89(8)\; \AA^3,\; T=295K,\; Z=1,\; D_c=1.504Mgm^{-3}$The intensity data were collected on an Enraf-Nonius CAD-4 Diffractometer with graphite monochromated $MoK\alpha$ radiation $(\alpha=0.7107\;\AA)$. The molecular structure was solved by direct method.』 and refined by full-matrix least squares to a final $R=2.47\%$ for 1659 unique observed $F_0>4\sigma(F_0)$ reflections and 234 parameters.

X-선 회절법을 이용하여 $C_{16}H_{19}O_2N_3CuCl_2\;{\cdot}\;H_2O$의 분자 및 결정구조를 해석하였다. 이 결정의 결정계는 Triclinic이고 공간군은 Pl이며, 단위포 상수는 $a=7.6202(9)\;{\AA},\;b=8.5943(7){\AA},\;c= 8.6272(6){\AA},\;\alpha=67.518(6)^{\circ},\; \beta= 68.043(8)^{\circ},\;\gamma=74.370(8)^{\circ},\;V=478.89(8)\;{\AA}^3,\;T=295K,\; Z=1,\;D_c=1.504Mgm^{-3}$이다. 회절반점들의 세기는 Enraf-Nonius CAD-4 Diffractometer로 얻었으며 graphite로. 단색화한 $MoK{\alpha}$,$(\alpha=0.7107\;\AA)$을 사용하였다. 분자구조는 Direct method로 풀었으며, $F_0>4\sigma(F_0)$인 1659개의 독립회절데이터에 대하여 최소 자승법으로 234개의 변수를 정밀화하여 최종 신뢰도 값 $R=2.47\%$를 얻었다.

Keywords

References

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