Abstract
A method of synthesizing $NaAlCO_3(OH)_2$ (Dawsonite) and $KAlCO_3(OH)_2$, was investigated by blowing $CO_2$ gas into sodium and potassium aluminate solutions. The reactions were accomplished at a temperature of 80 to $90^{\circ}C$, while $CO_2$ gas was blowing into the solutions which the molar ratios of $Na_2O/Al_2O_3,\;and\;K_2O/Al_2O_3$ were 6 to 8 and 8 to 10, respectively. It was observed that highly purified Dawsonite and $KAlCO_3(OH)_2$ are produced when Alumina is present in Boehmite at an equilibrium solid phase with a large amount of $HCO_3^-$ in the solutions. The rational formulas of Dawsonite and $KAlCO_3(OH)_2$synthesized under the conditions should be expressed as $NaAlO(OH)HCO_3\;and\;KAlO(OH)HCO_3$, respectively, by IR analysis. In addition, electron microscopic observation also indicated that Dawsonite in a fibrous crystal and $KAlCO_3(OH)_2$ in a needleshaped crystal.
알루민산나트륨과 알루민산칼륨 용액에 $CO_2$가스 吹入法에 의해 $NaAlCO_3(OH)_2\;(Dawsonite)와\;KAlCO_3(OH)_2$를 合成하였다. 이 反應은 80 ∼ $90^{\circ}C$에서 $Na_2O/Al_2O_3,\;K_2O/Al_2O_3$의 몰比가 各 各 6∼8, 8∼10인 알루민산알칼리 용액중에 $CO_2$가스를 吹?하여 達成되었다. 알루민산알칼리 용액중에 $HCO_3^-$이 多量 存在하며 알루미나가 平衡固相으로서 Boehmite로 存在할 때 高純度의 Dawsonate와 $KAlCO_3(OH)_2$가 生成된다는 것을 알았다. 이런 條件下에서 合成된 Dawsonite와 $KAlCO_3(OH)_2$의 示性式은 赤外線吸收스펙트럼 分析結果 各各 $NaAlO(OH)HCO_3와\;KAlO(OH)HCO_3$로 나타내는 것이 妥當하다고 생각된다. 또 電子顯微鏡觀察로부터 Dawsonite는 纖維狀結晶, $KAlCO_3(OH)_2$는 針狀結晶으로 되어 있다는 것을 알았다.